What will be the output of the following C++ code?
#include <iostream>
#include <memory>
#include <string>
using namespace std;
int main ()
{
string numbers[] = {"steve", "jobs"};
pair <string*, ptrdiff_t> result = get_temporary_buffer<string>(2);
if (result.second>0)
{
uninitialized_copy ( numbers, numbers + result.second, result.first );
for (int i = 0; i < result.second; i++)
cout << result.first[i] << " ";
return_temporary_buffer(result.first);
}
return 0;
}
#include <iostream>
#include <memory>
#include <string>
using namespace std;
int main ()
{
string numbers[] = {"steve", "jobs"};
pair <string*, ptrdiff_t> result = get_temporary_buffer<string>(2);
if (result.second>0)
{
uninitialized_copy ( numbers, numbers + result.second, result.first );
for (int i = 0; i < result.second; i++)
cout << result.first[i] << " ";
return_temporary_buffer(result.first);
}
return 0;
}A. steve
B. jobs
C. jobs steve
D. steve jobs
Answer: Option D
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it

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