What will be the output of the following C++ code?
#include <iostream>
using namespace std;
template <class T>
T max (T& a, T& b)
{
return (a>b?a:b);
}
int main ()
{
int i = 5, j = 6, k;
long l = 10, m = 5, n;
k = max(i, j);
n = max(l, m);
cout << k << endl;
cout << n << endl;
return 0;
}
#include <iostream>
using namespace std;
template <class T>
T max (T& a, T& b)
{
return (a>b?a:b);
}
int main ()
{
int i = 5, j = 6, k;
long l = 10, m = 5, n;
k = max(i, j);
n = max(l, m);
cout << k << endl;
cout << n << endl;
return 0;
}A. 6
B. 6
10
C. 5
10
D. 5
Answer: Option B
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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