What will be the output of the following C++ code?
#include <iostream>
using namespace std;
template <typename T>
void fun(const T&x)
{
static int count = 0;
cout << "x = " << x << " count = " << count;
++count;
return;
}
int main()
{
fun<int> (1);
cout << endl;
fun<int>(1);
cout << endl;
fun<double>(1.1);
cout << endl;
return 0;
}
#include <iostream>
using namespace std;
template <typename T>
void fun(const T&x)
{
static int count = 0;
cout << "x = " << x << " count = " << count;
++count;
return;
}
int main()
{
fun<int> (1);
cout << endl;
fun<int>(1);
cout << endl;
fun<double>(1.1);
cout << endl;
return 0;
}A. x = 1 count = 0
x = 1 count = 1
x = 1.1 count = 0
B. x = 1 count = 0
x = 1.0 count = 1.0
x = 1.1 count = 0
C. x = 1.0 count = 0.0
x = 1 count = 1
x = 1.1 count = 0
D. x = 1.0 count = 0.0
x = 1.0 count = 1.0
x = 1.1 count = 0.0
Answer: Option A
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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