What will be the output of the following C++ code?
#include <iostream>
using namespace std;
template<typename type>
class Test
{
public:
Test()
{
};
~Test()
{
};
type Funct1(type Var1)
{
return Var1;
}
type Funct2(type Var2)
{
return Var2;
}
};
int main()
{
Test<int> Var1;
Test<float> Var2;
cout << Var1.Funct1(200) << endl;
cout << Var2.Funct2(3.123) << endl;
return 0;
}
#include <iostream>
using namespace std;
template<typename type>
class Test
{
public:
Test()
{
};
~Test()
{
};
type Funct1(type Var1)
{
return Var1;
}
type Funct2(type Var2)
{
return Var2;
}
};
int main()
{
Test<int> Var1;
Test<float> Var2;
cout << Var1.Funct1(200) << endl;
cout << Var2.Funct2(3.123) << endl;
return 0;
}A. 200
3.123
B. 3.123
200
C. 200
D. 3.123
Answer: Option A
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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