What will be the output of the following C++ code?
#include <iostream>
#include <functional>
#include <algorithm>
using namespace std;
int main ()
{
int first[] = {10, 40, 90};
int second[] = {1, 2, 3};
int results[5];
transform ( first, first + 5, second, results, divides<int>());
for (int i = 0; i < 3; i++)
cout << results[i] << " ";
return 0;
}
#include <iostream>
#include <functional>
#include <algorithm>
using namespace std;
int main ()
{
int first[] = {10, 40, 90};
int second[] = {1, 2, 3};
int results[5];
transform ( first, first + 5, second, results, divides<int>());
for (int i = 0; i < 3; i++)
cout << results[i] << " ";
return 0;
}A. 10 20
B. 20 30
C. 10 20 30
D. 20 40
Answer: Option C
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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