What will be the output of the following C++ code?
#include <iostream>
using namespace std;
class BaseClass
{
int i;
public:
void setInt(int n);
int getInt();
};
class DerivedClass : public BaseClass
{
int j;
public:
void setJ(int n);
int mul();
};
void BaseClass::setInt(int n)
{
i = n;
}
int BaseClass::getInt()
{
return i;
}
void DerivedClass::setJ(int n)
{
j = n;
}
int DerivedClass::mul()
{
return j * getInt();
}
int main()
{
DerivedClass ob;
ob.setInt(10);
ob.setJ(4);
cout << ob.mul();
return 0;
}
#include <iostream>
using namespace std;
class BaseClass
{
int i;
public:
void setInt(int n);
int getInt();
};
class DerivedClass : public BaseClass
{
int j;
public:
void setJ(int n);
int mul();
};
void BaseClass::setInt(int n)
{
i = n;
}
int BaseClass::getInt()
{
return i;
}
void DerivedClass::setJ(int n)
{
j = n;
}
int DerivedClass::mul()
{
return j * getInt();
}
int main()
{
DerivedClass ob;
ob.setInt(10);
ob.setJ(4);
cout << ob.mul();
return 0;
}A. 10
B. 4
C. 40
D. 30
Answer: Option C
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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