What will be the output of the following C++ code?
#include <vector>
#include <iostream>
#include <typeinfo>
#include <stdexcept>
using namespace std;
int main()
{
vector<int> vec;
vec.push_back(10);
int i = vec[100];
try {
i = vec[0];
cout << i << endl;
}
catch (exception &e)
{
cout << "Caught: " << e.what( ) << endl;
cout << "Type: " << typeid( e ).name( ) << endl;
}
catch (...)
{
cout << "Unknown exception: " << endl;
}
return 0;
}
#include <vector>
#include <iostream>
#include <typeinfo>
#include <stdexcept>
using namespace std;
int main()
{
vector<int> vec;
vec.push_back(10);
int i = vec[100];
try {
i = vec[0];
cout << i << endl;
}
catch (exception &e)
{
cout << "Caught: " << e.what( ) << endl;
cout << "Type: " << typeid( e ).name( ) << endl;
}
catch (...)
{
cout << "Unknown exception: " << endl;
}
return 0;
}A. 10
B. 100
C. Exception
D. Error
Answer: Option A
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it

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