What will be the output of the following C++ code?
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
template<class T>
class A
{
T a;
public:
A(){}
~A(){}
};
int main(int argc, char const *argv[])
{
A <char>a1;
A <int>a2;
A <double>a3;
cout<<sizeof(a1)<<endl;
cout<<sizeof(a2)<<endl;
cout<<sizeof(a3)<<endl;
return 0;
}
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
template<class T>
class A
{
T a;
public:
A(){}
~A(){}
};
int main(int argc, char const *argv[])
{
A <char>a1;
A <int>a2;
A <double>a3;
cout<<sizeof(a1)<<endl;
cout<<sizeof(a2)<<endl;
cout<<sizeof(a3)<<endl;
return 0;
}A. 1
4
8
B. 4
1
8
C. 1
1
1
D. 4
4
4
Answer: Option A
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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