What will be the output of the following C++ code?
#include <iostream>
using namespace std;
struct A
{
int i;
char j;
float f;
void func();
};
void A :: func() {}
struct B
{
public:
int i;
char j;
float f;
void func();
};
void B :: func() {}
int main()
{
A a; B b;
a.i = b.i = 1;
a.j = b.j = 'c';
a.f = b.f = 3.14159;
a.func();
b.func();
cout << "Allocated";
return 0;
}
#include <iostream>
using namespace std;
struct A
{
int i;
char j;
float f;
void func();
};
void A :: func() {}
struct B
{
public:
int i;
char j;
float f;
void func();
};
void B :: func() {}
int main()
{
A a; B b;
a.i = b.i = 1;
a.j = b.j = 'c';
a.f = b.f = 3.14159;
a.func();
b.func();
cout << "Allocated";
return 0;
}A. Allocated
B. Error
C. 3.14159
D. 1
Answer: Option A
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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