What will be the output of the following C++ code?
#include <iostream>
#include <iterator>
#include <list>
using namespace std;
int main ()
{
list<int> mylist;
for (int i = 0; i < 5; i++)
mylist.push_back (i * 20);
list<int> :: iterator first = mylist.begin();
list<int> :: iterator last = mylist.end();
cout << distance(first, last) << endl;
return 0;
}
#include <iostream>
#include <iterator>
#include <list>
using namespace std;
int main ()
{
list<int> mylist;
for (int i = 0; i < 5; i++)
mylist.push_back (i * 20);
list<int> :: iterator first = mylist.begin();
list<int> :: iterator last = mylist.end();
cout << distance(first, last) << endl;
return 0;
}A. 20
B. 100
C. 5
D. 15
Answer: Option C
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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