What will be the output of the following C++ code?
#include <iostream>
using namespace std;
template <class T>
inline T square(T x)
{
T result;
result = x * x;
return result;
};
template <>
string square<string>(string ss)
{
return (ss+ss);
};
int main()
{
int i = 4, ii;
string ww("A");
ii = square<int>(i);
cout << i << ii;
cout << square<string>(ww) << endl;
}
#include <iostream>
using namespace std;
template <class T>
inline T square(T x)
{
T result;
result = x * x;
return result;
};
template <>
string square<string>(string ss)
{
return (ss+ss);
};
int main()
{
int i = 4, ii;
string ww("A");
ii = square<int>(i);
cout << i << ii;
cout << square<string>(ww) << endl;
}A. 416AA
B. 164AA
C. AA416
D. AA41A
Answer: Option A
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
Join The Discussion