What will be the output of the following C++ code?
#include <iostream>
using namespace std;
class BaseClass
{
public:
virtual void myFunction()
{
cout << "1";
}
};
class DerivedClass1 : public BaseClass
{
public:
void myFunction()
{
cout << "2";
}
};
class DerivedClass2 : public DerivedClass1
{
public:
void myFunction()
{
cout << "3";
}
};
int main()
{
BaseClass *p;
BaseClass ob;
DerivedClass1 derivedObject1;
DerivedClass2 derivedObject2;
p = &ob;
p -> myFunction();
p = &derivedObject1;
p -> myFunction();
p = &derivedObject2;
p -> myFunction();
return 0;
}
#include <iostream>
using namespace std;
class BaseClass
{
public:
virtual void myFunction()
{
cout << "1";
}
};
class DerivedClass1 : public BaseClass
{
public:
void myFunction()
{
cout << "2";
}
};
class DerivedClass2 : public DerivedClass1
{
public:
void myFunction()
{
cout << "3";
}
};
int main()
{
BaseClass *p;
BaseClass ob;
DerivedClass1 derivedObject1;
DerivedClass2 derivedObject2;
p = &ob;
p -> myFunction();
p = &derivedObject1;
p -> myFunction();
p = &derivedObject2;
p -> myFunction();
return 0;
}A. 123
B. 12
C. 213
D. 321
Answer: Option A
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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