What will be the output of the following C++ code?
#include <iostream>
#include <complex>
using namespace std;
int main()
{
complex <double> cn(3.0, 4.0);
auto cnj = conj(cn);
cout<<"Conjugate of "<<real(cn)<<"+("<<imag(cn)<<")i is: "<<real(cnj)<<"
+("<<imag(cnj)<<")i"<<endl;
return 0;
}
#include <iostream>
#include <complex>
using namespace std;
int main()
{
complex <double> cn(3.0, 4.0);
auto cnj = conj(cn);
cout<<"Conjugate of "<<real(cn)<<"+("<<imag(cn)<<")i is: "<<real(cnj)<<"
+("<<imag(cnj)<<")i"<<endl;
return 0;
}A. Conjugate of 3+(4)i is: 3+(4)i
B. Conjugate of 3+(4)i is: 3-(-4)i
C. Conjugate of 3+(4)i is: 3-(+4)i
D. Conjugate of 3+(4)i is: 3+(-4)i
Answer: Option D
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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