What will be the output of the following C++ code?
#include <iostream>
using namespace std;
class Base
{
public:
virtual void print() const = 0;
};
class DerivedOne : virtual public Base
{
public:
void print() const
{
cout << "1";
}
};
class DerivedTwo : virtual public Base
{
public:
void print() const
{
cout << "2";
}
};
class Multiple : public DerivedOne, DerivedTwo
{
public:
void print() const
{
DerivedTwo::print();
}
};
int main()
{
Multiple both;
DerivedOne one;
DerivedTwo two;
Base *array[ 3 ];
array[ 0 ] = &both;
array[ 1 ] = &one;
array[ 2 ] = &two;
for ( int i = 0; i < 3; i++ )
array[ i ] -> print();
return 0;
}
#include <iostream>
using namespace std;
class Base
{
public:
virtual void print() const = 0;
};
class DerivedOne : virtual public Base
{
public:
void print() const
{
cout << "1";
}
};
class DerivedTwo : virtual public Base
{
public:
void print() const
{
cout << "2";
}
};
class Multiple : public DerivedOne, DerivedTwo
{
public:
void print() const
{
DerivedTwo::print();
}
};
int main()
{
Multiple both;
DerivedOne one;
DerivedTwo two;
Base *array[ 3 ];
array[ 0 ] = &both;
array[ 1 ] = &one;
array[ 2 ] = &two;
for ( int i = 0; i < 3; i++ )
array[ i ] -> print();
return 0;
}A. 121
B. 212
C. 12
D. 215
Answer: Option B
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it

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