What will be the output of the following C++ code?
#include <iostream>
#include <exception>
#include <typeinfo>
using namespace std;
class Test1
{
virtual int Funct()
{
}
};
int main ()
{
try
{
Test1 * var = NULL;
typeid (*var);
}
catch (std::exception& typevar)
{
cout << "Exception: " << typevar.what() << endl;
}
return 0;
}
#include <iostream>
#include <exception>
#include <typeinfo>
using namespace std;
class Test1
{
virtual int Funct()
{
}
};
int main ()
{
try
{
Test1 * var = NULL;
typeid (*var);
}
catch (std::exception& typevar)
{
cout << "Exception: " << typevar.what() << endl;
}
return 0;
}A. NULL
B. Exception:bad_alloc
C. Exception:std:bad_typeid
D. Exception:std:bad_type
Answer: Option C
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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