What will be the output of the following C++ code?
#include <iostream>
using namespace std;
class A
{
public:
A(int n )
{
cout << n;
}
};
class B: public A
{
public:
B(int n, double d)
: A(n)
{
cout << d;
}
};
class C: public B
{
public:
C(int n, double d, char ch)
: B(n, d)
{
cout <<ch;
}
};
int main()
{
C c(5, 4.3, 'R');
return 0;
}
#include <iostream>
using namespace std;
class A
{
public:
A(int n )
{
cout << n;
}
};
class B: public A
{
public:
B(int n, double d)
: A(n)
{
cout << d;
}
};
class C: public B
{
public:
C(int n, double d, char ch)
: B(n, d)
{
cout <<ch;
}
};
int main()
{
C c(5, 4.3, 'R');
return 0;
}A. 54.3R
B. R4.35
C. 4.3R5
D. R2.6
Answer: Option A
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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