What will be the output of the following C++ code?
#include <iostream>
using namespace std;
class sample
{
public:
virtual void example() = 0;
};
class Ex1:public sample
{
public:
void example()
{
cout << "ubuntu";
}
};
class Ex2:public sample
{
public:
void example()
{
cout << " is awesome";
}
};
int main()
{
sample* arra[2];
Ex1 e1;
Ex2 e2;
arra[0]=&e1;
arra[1]=&e2;
arra[0]->example();
arra[1]->example();
}
#include <iostream>
using namespace std;
class sample
{
public:
virtual void example() = 0;
};
class Ex1:public sample
{
public:
void example()
{
cout << "ubuntu";
}
};
class Ex2:public sample
{
public:
void example()
{
cout << " is awesome";
}
};
int main()
{
sample* arra[2];
Ex1 e1;
Ex2 e2;
arra[0]=&e1;
arra[1]=&e2;
arra[0]->example();
arra[1]->example();
}A. ubuntu
B. is awesome
C. ubuntu is awesome
D. ubunt esome
Answer: Option C
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
Join The Discussion