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What will be the output of the following C++ code?
#include <iostream>
#include <array>
using namespace std;
int main(int argc, char const *argv[])
{
	array<int,5> arr = {1,2,3,4,5};
	cout<<"Printing Using [] operator: ";
	for(int i=0;i<5;i++){
		cout<<arr[i]<<" ";
	}
	cout<<endl;
	cout<<"Printing Using at() function: ";
	for(int i=0;i<5;i++){
		cout<<arr.at(i)<<" ";
	}
	cout<<endl;
	return 0;
}

A. 1 2 3 4 5
1 2 3 4 5

B. Printing Using [] operator: 1 2 3 4 5
Printing Using at() function: 1 2 3 4 5

C. Printing Using at() function: 1 2 3 4 5
Printing Using [] operator: 1 2 3 4 5

D. Printing Using at() function: 1 2 3 4 5

Answer: Option B


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Related Questions on C plus plus miscellaneous

What is the difference between '++i' and 'i++' in C++?

A. None of the above

B. They both have the same effect

C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it

D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it