What will be the output of the following C++ code?
#include <iostream>
#include <functional>
#include <numeric>
using namespace std;
int myaccumulator (int x, int y)
{
return x - y;
}
int myproduct (int x, int y)
{
return x + y;
}
int main ()
{
int a = 100;
int series1[] = {10, 20, 30};
int series2[] = {1, 2, 3};
cout << inner_product(series1, series1 + 3, series2, a ,myaccumulator,
myproduct);
cout << endl;
return 0;
}
#include <iostream>
#include <functional>
#include <numeric>
using namespace std;
int myaccumulator (int x, int y)
{
return x - y;
}
int myproduct (int x, int y)
{
return x + y;
}
int main ()
{
int a = 100;
int series1[] = {10, 20, 30};
int series2[] = {1, 2, 3};
cout << inner_product(series1, series1 + 3, series2, a ,myaccumulator,
myproduct);
cout << endl;
return 0;
}A. 40
B. 34
C. 32
D. 20
Answer: Option B
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it

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