What will be the output of the following C++ code?
#include <iostream>
using namespace std;
template <class type>
class Test
{
public:
Test();
~Test();
type Data(type);
};
template <class type>
type Test<type>::Data(type Var0)
{
return Var0;
}
template <class type>
Test<type>::Test()
{
}
template <class type>
Test<type>::~Test()
{
}
int main(void)
{
Test<char> Var3;
cout << Var3.Data('K') << endl;
return 0;
}
#include <iostream>
using namespace std;
template <class type>
class Test
{
public:
Test();
~Test();
type Data(type);
};
template <class type>
type Test<type>::Data(type Var0)
{
return Var0;
}
template <class type>
Test<type>::Test()
{
}
template <class type>
Test<type>::~Test()
{
}
int main(void)
{
Test<char> Var3;
cout << Var3.Data('K') << endl;
return 0;
}A. k
B. l
C. error
D. runtime error
Answer: Option A
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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