What will be the output of the following C++ code?
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
template<class T>
class A
{
public:
A(){
cout<<"Created\n";
}
~A(){
cout<<"Destroyed\n";
}
};
int main(int argc, char const *argv[])
{
A <int>a1;
A <char>a2;
A <float>a3;
return 0;
}
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
template<class T>
class A
{
public:
A(){
cout<<"Created\n";
}
~A(){
cout<<"Destroyed\n";
}
};
int main(int argc, char const *argv[])
{
A <int>a1;
A <char>a2;
A <float>a3;
return 0;
}A. Created
Destroyed
Created
Destroyed
Created
Destroyed
B. Created
Created
Created
Destroyed
Destroyed
Destroyed
C. Destroyed
Created
Destroyed
Created
Destroyed
Created
D. Destroyed
Destroyed
Destroyed
Created
Created
Created
Answer: Option B
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it

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