What will be the output of the following code: for (int i = 5; i >= 0; --i) { cout << i << " "; if (i == 3) break; } in C++?
A. Compilation error
B. 5 4 3
C. 5 4 3 2 1 0
D. 5 4 3 0 1
Answer: Option C
Solution (By Examveda Team)
The given code is a for loop in C++:for (int i = 5; i >= 0; --i) {
cout << i << " ";
if (i == 3) break;
}
This loop initializes i to 5 and decrements it in each iteration until i becomes less than 0.
On each iteration, it prints the current value of i followed by a space.
When i becomes 3, the if condition becomes true and the break statement terminates the loop.
Therefore, the values printed are: 5 4 3
No further values (like 2, 1, 0) are printed because the loop exits when i == 3.
Hence, the correct output is: 5 4 3
This Question Belongs to C Plus Plus Programming >> Control Flow Statements In C Plus Plus
the correct answer is
5 4 3
becuse the loop is stop when ( i = 3 )