What will be the output of the following Java code?
class A
{
public void m1 (int i,float f)
{
System.out.println(" int float method");
}
public void m1(float f,int i);
{
System.out.println("float int method");
}
public static void main(String[]args)
{
A a=new A();
a.m1(20,20);
}
}
class A
{
public void m1 (int i,float f)
{
System.out.println(" int float method");
}
public void m1(float f,int i);
{
System.out.println("float int method");
}
public static void main(String[]args)
{
A a=new A();
a.m1(20,20);
}
}A. int float method
B. float int method
C. compile time error
D. run time error
Answer: Option C
This Question Belongs to Java Program >> Overriding And Overloading
What is method overriding in Java?
A. Redefining a superclass method in a subclass
B. Defining a new method with the same name in a subclass
C. Making a method private in a subclass
D. Hiding methods in a superclass
What is the purpose of method overloading in Java?
A. Creating static methods
B. Hiding methods in a superclass
C. Redefining methods in a subclass
D. Defining multiple methods with the same name but different parameters
A. @OverrideMethod
B. @OverrideSuper
C. @Override
D. @OverrideParent
What happens when a subclass tries to override a final method from the superclass in Java?
A. The final method is hidden
B. It results in a compilation error
C. The final method becomes static
D. The final method is hidden
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