What will be the output of the following Java code?
class overload
{
int x;
double y;
void add(int a , int b)
{
x = a + b;
}
void add(double c , double d)
{
y = c + d;
}
overload()
{
this.x = 0;
this.y = 0;
}
}
class Overload_methods
{
public static void main(String args[])
{
overload obj = new overload();
int a = 2;
double b = 3.2;
obj.add(a, a);
obj.add(b, b);
System.out.println(obj.x + " " + obj.y);
}
}
class overload
{
int x;
double y;
void add(int a , int b)
{
x = a + b;
}
void add(double c , double d)
{
y = c + d;
}
overload()
{
this.x = 0;
this.y = 0;
}
}
class Overload_methods
{
public static void main(String args[])
{
overload obj = new overload();
int a = 2;
double b = 3.2;
obj.add(a, a);
obj.add(b, b);
System.out.println(obj.x + " " + obj.y);
}
}A. 6 6
B. 6.4 6.4
C. 6.4 6
D. 4 6.4
Answer: Option D
This Question Belongs to Java Program >> Overriding And Overloading
What is method overriding in Java?
A. Redefining a superclass method in a subclass
B. Defining a new method with the same name in a subclass
C. Making a method private in a subclass
D. Hiding methods in a superclass
What is the purpose of method overloading in Java?
A. Creating static methods
B. Hiding methods in a superclass
C. Redefining methods in a subclass
D. Defining multiple methods with the same name but different parameters
A. @OverrideMethod
B. @OverrideSuper
C. @Override
D. @OverrideParent
What happens when a subclass tries to override a final method from the superclass in Java?
A. The final method is hidden
B. It results in a compilation error
C. The final method becomes static
D. The final method is hidden
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