What will be the output of the following PHP code ?
<?php
$x = 4;
$y = 3;
function fun($x = 3, $y = 4)
{
$z = $x+$y/$y+$x;
echo "$z";
}
echo $x;
echo $y;
echo $z;
fun($x, $y);
?>
<?php
$x = 4;
$y = 3;
function fun($x = 3, $y = 4)
{
$z = $x+$y/$y+$x;
echo "$z";
}
echo $x;
echo $y;
echo $z;
fun($x, $y);
?>
A. 43
B. 943
C. 349
D. 439
Answer: Option D
Solution(By Examveda Team)
Firstly, the statements outside the function are printed, since z is not defined it’ll no value is printed for z. Next the function is called and the value of z inside the function is printed.This Question Belongs to PHP >> Operators And Expressions In Php
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