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What will be the output of the following Python code?
What will be the output of the following Python code?
l=[]
def convert(b):
if(b==0):
return l
dig=b%2
l.append(dig)
convert(b//2)
convert(6)
l.reverse()
for i in l:
print(i,end="")
l=[]
def convert(b):
if(b==0):
return l
dig=b%2
l.append(dig)
convert(b//2)
convert(6)
l.reverse()
for i in l:
print(i,end="")
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