What will be the output of the following Python code snippet?
numbers = {}
letters = {}
comb = {}
numbers[1] = 56
numbers[3] = 7
letters[4] = 'B'
comb['Numbers'] = numbers
comb['Letters'] = letters
print(comb)
numbers = {}
letters = {}
comb = {}
numbers[1] = 56
numbers[3] = 7
letters[4] = 'B'
comb['Numbers'] = numbers
comb['Letters'] = letters
print(comb)A. Error, dictionary in a dictionary can't exist
B. Numbers': {1: 56, 3: 7}
C. {'Numbers': {1: 56}, 'Letters': {4: 'B'}}
D. {'Numbers': {1: 56, 3: 7}, 'Letters': {4: 'B'}}
Answer: Option D
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