What will be the output of the program?
#include<stdio.h>
void main()
{
int a[5] = {5, 1, 15, 20, 25};
int i, j, m;
i = ++a[1];
j = a[1]++;
m = a[i++];
printf("%d, %d, %d", i, j, m);
}
#include<stdio.h>
void main()
{
int a[5] = {5, 1, 15, 20, 25};
int i, j, m;
i = ++a[1];
j = a[1]++;
m = a[i++];
printf("%d, %d, %d", i, j, m);
}A. 3, 2, 15
B. 2, 3, 20
C. 2, 1, 15
D. 1, 2, 5
Answer: Option A
Solution(By Examveda Team)
>> int a[5] = {5, 1, 15, 20, 25}; The variable arr is declared as an integer array with a size of 5 and it is initialized to
a[0] = 5, a[1] = 1, a[2] = 15, a[3] = 20, a[4] = 25.
>> int i, j, m; The variable i, j, m are declared as an integer type.
>> i = ++a[1]; becomes i = ++1; Hence i = 2 and a[1] = 2
>> j = a[1]++; becomes j = 2++; Hence j = 2 and a[1] = 3.
>> m = a[i++]; becomes m = a[2]; Hence m = 15 and i is incremented by 1(i++ means 2++ so i=3)
>> printf("%d, %d, %d", i, j, m); It prints the value of the variables i, j, m
Hence the output of the program is 3, 2, 15.
This Question Belongs to C Program >> Arrays And Strings
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Comments ( 12 )
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Good explanation, thank you
option no B should be correct please look into seriously
This answer will be b.
Perect explanation
Sir j = a[1]++ so first the value will be stored i think then the incrementation will be done so j = 2 will right
The ans is b
Hw cm a[1] =2 ? as till i=2 i.e. in the first step..
Can u explain the reaaon for that in detail...
The value of i is supposed to be 2 right?
Hello Pradeep
Please check the sixth line of explanation for a doubt you have in mind.
the value of i=2 as written by you but it varies in option.also the value of m would be a[3]=20 not 15.
Hello Pradyumna,
Please read explanation clearly.
sir the value of a[1] will be 1 on i as well as on j so the ans will be 2, 1, 15