What will be the output of the program?
#include<stdio.h>
#include<string.h>
void main()
{
char str1[20] = "Hello", str2[20] = " World";
printf("%s", strcpy(str2, strcat(str1, str2)));
}
#include<stdio.h>
#include<string.h>
void main()
{
char str1[20] = "Hello", str2[20] = " World";
printf("%s", strcpy(str2, strcat(str1, str2)));
}A. Hello World
B. World
C. WorldHello
D. Hello
E. None of these
Answer: Option A
Solution (By Examveda Team)
>> char str1[20] = "Hello", str2[20] = " World"; The variable str1 and str2 is declared as an array of characters and initialized with value "Hello" and " World" respectively.>> printf("%sn", strcpy(str2, strcat(str1, str2)));
=> strcat(str1, str2) it append the string str2 to str1. The result will be stored in str1. Therefore str1 contains "Hello World".
=> strcpy(str2, "Hello World") it copies the "Hello World" to the variable str2.
Hence it prints "Hello World".
This Question Belongs to C Program >> Arrays And Strings
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Comments (4)
Related Questions on Arrays and Strings
Why it is not world hello world
when concatenated str1 is copied to str 2 wouldn't it be worldhelloworld?
can some someone explain y its is only hello world
i didnt get the logic
The result will be "hello world"