What will be the output of the program if the array begins at address 65486? #includelt;stdio.h> void main() int arr[] = 12, 14, 15, 23, 45; printf("%u, %u", arr, arr);

gt;gt; int arr[] = 12, 14, 15, 23, 45; The variable arr is declared as an integer array and initialized. gt;gt; printf(%u, %u, arr, amp;arr); Here, The base address of the array is 65486. =gt; arr, amp;arr is pointing to the base address of the array arr. Hence the output of the program is 65486, 65486.

What will be the output of the program if the array...

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What will be the output of the program if the array begins at address 65486?

#include<stdio.h>
void main()
{
    int arr[] = {12, 14, 15, 23, 45};
    printf("%u, %u", arr, &arr);
}

A) 65486, 65488 B) 65486, 65490 C) 65486, 65487 D) 65486, 65486 E) None of these

Answer & Solution

Correct Answer: Option D

>> int arr[] = {12, 14, 15, 23, 45}; The variable arr is declared as an integer array and initialized.

>> printf("%u, %u", arr, &arr); Here,
The base address of the array is 65486.

=> arr, &arr is pointing to the base address of the array arr.
Hence the output of the program is 65486, 65486.

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Hareesh K.m 8 years ago

what is &arr means??

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What will be the output of the program if the array...

What will be the output of the program if the array begins at address 65486? #include<stdio.h> void main() { int arr[] = {12, 14, 15, 23, 45}; printf("%u, %u", arr, &arr); }

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What will be the output of the program if the array begins at address 65486?

`#include<stdio.h> void main() { int arr[] = {12, 14, 15, 23, 45}; printf("%u, %u", arr, &arr); }`