What will be the output of this program on an implementation where "int" occupies 2 bytes?

#include <stdio.h>
void main()
{
      int i = 3;
      int j;
      j = sizeof(++i + ++i);
      printf("i=%d j=%d", i, j);
}

A. i=4 j=2

B. i=3 j=2

C. i=5 j=2

D. the behavior is undefined

Answer: Option B

Solution(By Examveda Team)

Evaluating ++i + ++i would produce undefined behavior, but the operand of sizeof is not evaluated, so i remains 3 throughout the program. The type of the expression (int) is reduced at compile time, and the size of this type (2) is assigned to j.