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What will be the result after compiling this code?
What will be the result after compiling this code?
class SuperClass{
public int doIt(String str, Integer... data)throws Exception{
String signature = "(String, Integer[])";
System.out.println(str + " " + signature);
return 1;
}
}
public class Test extends SuperClass{
public int doIt(String str, Integer... data){
String signature = "(String, Integer[])";
System.out.println("Overridden: " + str + " " +signature);
return 0;
}
public static void main(String... args){
SuperClass sb = new Test();
sb.doIt("hello", 3);
}
}
class SuperClass{
public int doIt(String str, Integer... data)throws Exception{
String signature = "(String, Integer[])";
System.out.println(str + " " + signature);
return 1;
}
}
public class Test extends SuperClass{
public int doIt(String str, Integer... data){
String signature = "(String, Integer[])";
System.out.println("Overridden: " + str + " " +signature);
return 0;
}
public static void main(String... args){
SuperClass sb = new Test();
sb.doIt("hello", 3);
}
}
Answer & Solution
Correct Answer:
Option
C
Exception must be caught or declared to be thrown.
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LoginRule: If you are calling a method that declares an exception, you must either caught or declare the exception.
There are two cases:
Case1:You caught the exception i.e. handle the exception using try/catch.
Case2:You declare the exception i.e. specifying throws with the method.