What will be the value stored in arr[2][2] when the following code is executed?

#include<stdio.h>
int get_ways(int num_of_dice, int num_of_faces, int S)
{
      int arr[num_of_dice + 1][S + 1];
      int dice, face, sm;
      for(dice = 0; dice <= num_of_dice; dice++)
         for(sm = 0; sm <= S; sm++)
           arr[dice][sm] = 0;
      for(sm = 1; sm <= S; sm++)
           arr[1][sm] = 1;
      for(dice = 2; dice <= num_of_dice; dice++)
      {
          for(sm = 1; sm <= S; sm++)
          {
              for(face = 1; face <= num_of_faces && face < sm; face++)
                  arr[dice][sm] += arr[dice - 1][sm - face];
          }
      }
      return arr[num_of_dice][S];
}
int main()
{
      int num_of_dice = 3, num_of_faces = 4, sum = 6;
      int ans = get_ways(num_of_dice, num_of_faces, sum);
      printf("%d",ans);
      return 0;
}

A. 0

B. 1

C. 2

D. 3

Answer: Option B