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When the speed of belt increases,
Answer & Solution
Correct Answer:
Option
D
When the speed of the belt increases
The power transmitted by a belt drive is directly proportional to the product of the belt tension and the belt speed
Power (P) = (T₁ - T₂) × v, where T₁ is the tension in the tight side, T₂ is the tension in the slack side, and v is the belt speed
As the belt speed increases, assuming the tensions remain constant, the power transmitted also increases
However, there's a practical limit to this, because at very high speeds, centrifugal force increases and reduces the effective friction and tension difference
But initially, with an increase in speed, the power transmitted increases
The power transmitted by a belt drive is directly proportional to the product of the belt tension and the belt speed
Power (P) = (T₁ - T₂) × v, where T₁ is the tension in the tight side, T₂ is the tension in the slack side, and v is the belt speed
As the belt speed increases, assuming the tensions remain constant, the power transmitted also increases
However, there's a practical limit to this, because at very high speeds, centrifugal force increases and reduces the effective friction and tension difference
But initially, with an increase in speed, the power transmitted increases
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LoginMost logical answer is friction decreases.
Simply due to the fact that decrease in friction will cause slip of belt ergo reduction in power transmitted.
it should be D