Examveda

Which of the following expressions for total binding energy B of a nucleus is correct (a1, a2, a3, a4 > 0?

A. $$B = {a_1}A - {a_2}{A^{2/3}} - {a_3}\frac{{Z\left( {Z - 1} \right)}}{{{A^{1/3}}}} - {a_4}\frac{{{{\left( {A - 2Z} \right)}^2}}}{A} + \delta $$

B. $$B = {a_1}A + {a_2}{A^{2/3}} - {a_3}\frac{{Z\left( {Z - 1} \right)}}{{{A^{1/3}}}} - {a_4}\frac{{{{\left( {A - 2Z} \right)}^2}}}{A} + \delta $$

C. $$B = {a_1}A + {a_2}{A^{1/3}} - {a_3}\frac{{Z\left( {Z - 1} \right)}}{{{A^{1/3}}}} - {a_4}\frac{{{{\left( {A - 2Z} \right)}^2}}}{A} + \delta $$

D. $$B = {a_1}A - {a_2}{A^{1/3}} - {a_3}\frac{{Z\left( {Z - 1} \right)}}{{{A^{1/3}}}} - {a_4}\frac{{{{\left( {A - 2Z} \right)}^2}}}{A} + \delta $$

Answer: Option A


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Related Questions on Nuclear and Particle Physics

The four possible configurations of neutrons in the ground state of $${}_4^9Be$$  nucleus according to the shell model, and the associated nuclear spin are listed below. Choose the correct one

A. $${\left( {{}^1{s_{1/2}}} \right)^2}{\left( {{}^1{p_{3/2}}} \right)^3};\,J = \frac{3}{2}$$

B. $${\left( {{}^1{s_{1/2}}} \right)^2}{\left( {{}^1{p_{1/2}}} \right)^2}{\left( {{}^1{p_{3/2}}} \right)^1};\,J = \frac{3}{2}$$

C. $${\left( {{}^1{s_{1/2}}} \right)^1}{\left( {{}^1{p_{3/2}}} \right)^4};\,J = \frac{1}{2}$$

D. $${\left( {{}^1{s_{1/2}}} \right)^2}{\left( {{}^1{p_{3/2}}} \right)^2}{\left( {{}^1{p_{1/2}}} \right)^1};\,J = \frac{1}{2}$$