ExamVeda
Login
Home
Chemical Engineering Thermodynamics
?

Which of the following is not correct for a reversible adiabatic process?

Answer & Solution
Correct Answer: Option D
An adiabatic process is represented by $$p{v^\gamma } = {\text{constant}}$$    now by replacing the $$p$$ with $$\frac{{nRT}}{v}$$  we get $$T{V^{\gamma - 1}} = {\text{constant}}$$    and by replacing the $$V$$ with $$\frac{{nRT}}{P}$$  we get the equation $${P^{1 - \gamma }}{T^\gamma } = {\text{constant}}.$$
Examveda
Question posted by Examveda
Community

Join the Discussion

No comments yet Be the first to discuss this question.