Which of the following is the correct expression that evaluates to true if the number x is between 1 and 100 or the number is negative?

Solution (By Examveda Team)

Let's break down this Java problem about operators! We want to find the expression that's true if 'x' is between 1 and 100 OR if 'x' is negative.

Option A: 1 < x < 100 || x < 0
This looks like it's checking if 'x' is between 1 and 100, or if 'x' is negative.
However, in Java, you cannot chain comparison operators like this (1 < x < 100). Java evaluates 1 < x first, which will return true or false, it will not compare to 100. So this option is wrong.

Option B: ((x < 100) && (x > 1)) || (x < 0)
Let's look at the first part: (x < 100) && (x > 1). This means 'x' must be less than 100 AND greater than 1. That's how we say "between 1 and 100 (not including 1 and 100)".
The '||' means "OR". So, it also checks if (x < 0), meaning 'x' is negative. If either of the conditions become true, it means that the whole expression evaluates to true.
This is the correct way to express the condition in Java.

Option C: ((x < 100) && (x > 1)) && (x < 0)
This option uses '&&' twice. '&&' means "AND". This means that 'x' must be between 1 and 100 AND also negative. A number cannot be both positive and negative, so this option will always be false. Therefore, this is not the correct option

Option D: (1 > x > 100) || (x < 0)
Similar to Option A, Java cannot chain comparison operators like this (1 > x > 100) so it will not behave as expected.
This looks like it's checking if 'x' is outside of 1 and 100, or if 'x' is negative, also similar to option A. 1 > x > 100 can not be chained like this.

Therefore, the correct answer is Option B.