Which of the following is the valid host range for the subnet on which the IP address 192.168.168.188 255.255.255.192 resides?
A. 192.168.168.129-190
B. 192.168.168.129-191
C. 192.168.168.128-190
D. 192.168.168.128-192
Answer: Option A
Solution(By Examveda Team)
256 - 192 = 64. 64 + 64 = 128. 128 + 64 = 192.The subnet is 128, the broadcast address is 191, and the valid host range is the numbers in between, or 129-190.
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But ye kiya kese ....like 256 minus than 64 add ....what is the process.....??
But ye kiya kese ....like 256 minus than 64 add ....what is the process.....??