Which of the following statement(s) is/are true.
$$\eqalign{
& {\text{I}}.\sqrt {64} + \sqrt {0.0064} + \sqrt {0.81} + \sqrt {0.0081} = 9.07 \cr
& {\text{II}}.\sqrt {0.010201} + \sqrt {98.01} + \sqrt {0.25} = 11.51 \cr} $$
A. Only I
B. Only II
C. Both I and II
D. Neither I nor II
Answer: Option A
Solution (By Examveda Team)
$$\eqalign{ & {\text{I}}.\sqrt {64} + \sqrt {0.0064} + \sqrt {0.81} + \sqrt {0.0081} = 9.07 \cr & {\text{L}}{\text{.H}}{\text{.S}}{\text{.}} = 8 + 0.08 + 0.9 + 0.09 \cr & = 9.07 = {\text{R}}{\text{.H}}{\text{.S}}{\text{.}} \cr & {\text{Hence, statement I is true}} \cr & {\text{II}}.\sqrt {0.010201} + \sqrt {98.01} + \sqrt {0.25} = 11.51 \cr & {\text{L}}{\text{.H}}{\text{.S}}{\text{.}} = \sqrt {{{\left( {0.101} \right)}^2}} + \sqrt {{{\left( {9.9} \right)}^2}} + \sqrt {{{\left( {0.5} \right)}^2}} \cr & = 0.101 + 9.9 + 0.5 \cr & = 10.501 \ne {\text{R}}{\text{.H}}{\text{.S}}{\text{.}} \cr & \Rightarrow {\text{Statement II is not true}} \cr} $$Related Questions on Surds and Indices
A. $$\frac{1}{2}$$
B. 1
C. 2
D. $$\frac{7}{2}$$
Given that 100.48 = x, 100.70 = y and xz = y2, then the value of z is close to:
A. 1.45
B. 1.88
C. 2.9
D. 3.7

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