# While packing for a business trip Mr. Debashis has packed 3 pairs of shoes, 4 pants, 3 half-pants,6 shirts, 3 sweater and 2 jackets. The outfit is defined as consisting of a pair of shoes, a choice of "lower wear" (either a pant or a half-pant), a choice of "upper wear" (it could be a shirt or a sweater or both) and finally he may or may not choose to wear a jacket. How many different outfits are possible?

A. 567

B. 1821

C. 743

D. 1701

**Answer: Option D **

__Solution(By Examveda Team)__

Number of ways a pair of shoes can be selected,=

^{3}C

_{1}

= 3 ways

Number of ways

**lower wear**can be selected = (3 + 4) = 7 ways.

Number of ways

**upper wear**can be selected, = 3 + 6 + (3 × 6)

= 27 ways

Number of ways jacket can be chosen or not chosen = 3 ways {No jacket, 1

^{st}jacket, 2

^{nd}jacket}.

Total number of different outfits

= 3 × 7 × 27 × 3

= 1701 ways

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