While packing for a business trip Mr. Debashis has packed 3 pairs of shoes, 4 pants, 3 half-pants,6 shirts, 3 sweater and 2 jackets. The outfit is defined as consisting of a pair of shoes, a choice of "lower wear" (either a pant or a half-pant), a choice of "upper wear" (it could be a shirt or a sweater or both) and finally he may or may not choose to wear a jacket. How many different outfits are possible?
A. 567
B. 1821
C. 743
D. 1701
Answer: Option D
Solution(By Examveda Team)
Number of ways a pair of shoes can be selected, = 3C1= 3 ways Number of ways lower wear can be selected = (3 + 4) = 7 ways. Number of ways upper wear can be selected, = 3 + 6 + (3 × 6)
= 27 ways Number of ways jacket can be chosen or not chosen = 3 ways {No jacket, 1st jacket, 2nd jacket}. Total number of different outfits
= 3 × 7 × 27 × 3
= 1701 ways
Related Questions on Permutation and Combination
A. 3! 4! 8! 4!
B. 3! 8!
C. 4! 4!
D. 8! 4! 4!
A. 7560,60,1680
B. 7890,120,650
C. 7650,200,4444
D. None of these
A. 8 × 9!
B. 8 × 8!
C. 7 × 9!
D. 9 × 8!
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