Why does JavaScript subset disallow == and !=?
A. It uses bitwise checking
B. It uses === and !== instead
C. It uses equals() and notequals() instead
D. None of the mentioned
Answer: Option B
Solution(By Examveda Team)
The subset does not include the comma operator, the bitwise operators, or the ++ and — operators. It also disallows == and != because of the type conversion they perform, requiring use of === and !== instead.Related Questions on Classes and Modules
The behaviour of the instances present of a class inside a method is defined by
A. Method
B. Classes
C. Interfaces
D. Classes and Interfaces
The keyword or the property that you use to refer to an object through which they were invoked is
A. from
B. to
C. this
D. object
Consider the following code snippet :
The output would be :var o = new F();
o.constructor === F
A. false
B. true
C. 0
D. 1
The basic difference between JavaScript and Java is
A. There is no difference
B. Functions are considered as fields
C. Variables are specific
D. Functions are values, and there is no hard distinction between methods and fields
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