Work speed of circular electrode of 220 mm diameter for carrying out seam welding at 4 welds per cm on 1.6 mm thick mild steel tube. Welding cycle consists of 3 cycles ‘on’ and 2 cycles ‘off’ Power supply is at 50 Hz. Calculate R.P.M. and energy requirement of the above circular electrodes assuming effective resistance between electrodes as 100 ohm.
A. 2.17 rpm, 600 joules
B. 6.8 rpm, 6 joules
C. 5.03 rpm, 600 joules
D. 22 rpm, 600 joules
Answer: Option A
This Question Belongs to Mechanical Engineering >> Manufacturing And Production Technology
Join The Discussion
Comments ( 1 )
Related Questions on Manufacturing and Production Technology
The carbide tools operating at very low cutting speeds (below 30 m/min)
A. Reduces tool life
B. Increases tool life
C. Have no effect on tool life
D. Spoils the work piece
The type of reamer used for reaming operation in a blind hole, is
A. Straight fluted reamer
B. Left hand spiral fluted reamer
C. Right hand spiral fluted reamer
D. Any one of these
High speed steel tools retain their hardness up to a temperature of
A. 250°C
B. 350°C
C. 500°C
D. 900°C
Weld per min = (frequency × 60)/ (cycles for weld + interval cycles)
= (50 × 60)/ (3 + 2) = 600 welds/ min.
Work speed (mm / min) = (welds/ min) / weld required per mm
= 600 / (4/10) = 1500 mm/ min.
Therefore, RPM of electrode = work speed in mm per min/ π × electrode diameter in mm
1500/ (3.14 × 220) = 2.17 rpm.
For 1.6 mm thick M.S. Plate, current requirement is around 10,000 amperes
Therefore, Energy required = I²RT = (10,000²) × 100 × (3/ 50) = 600 Joules.