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X and Y are partners in a firm having capital balances Rs. 1,08,000 and Rs. 72,000, respectively. They admit Z into a partnership for $${\frac{1}{3}^{{\text{rd}}}}$$ share, and Z brings proportion ate amount of capital. The capital amount of Z is

A. Rs. 22,500

B. Rs. 90,000

C. Rs. 1,80,000

D. Rs. 54,000

Answer: Option B


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Comments (2)

  1. Idas 1011
    Idas 1011:
    4 weeks ago

    Step 1: Find total capital of X and Y
    X = 108,000
    Y = 72,000

    Total = 108,000 + 72,000 = 180,000

    Step 2: Z is admitted for 1/3 share

    This means:

    Z’s capital should be 1/3 of total capital after admission

    Let total capital after admission = T

    Then:

    Z’s share = (1/3)T
    X and Y together = (2/3)T

    But we already know:

    X + Y = 180,000 = (2/3)T
    Step 3: Find total capital (T)
    2
    3
    š‘‡
    =
    180
    ,
    000
    3
    2
    ​

    T=180,000
    š‘‡
    =
    180
    ,
    000
    Ɨ
    3
    2
    =
    270
    ,
    000
    T=180,000Ɨ
    2
    3
    ​

    =270,000
    Step 4: Find Z’s capital
    š‘
    =
    1
    3
    Ɨ
    270
    ,
    000
    =
    90
    ,
    000
    Z=
    3
    1
    ​

    Ɨ270,000=90,000

  2. Nayem Uddin
    Nayem Uddin:
    2 years ago

    Capital Ratio of share X & Y is 3:2
    New Partner z Share 1/3

    Now, X= 3/5-1/3=4/15
    Y=2/5-1/3=1/15
    Z=1/3*5*5=5/15

    New Ratio=4:1:15
    Now total Capital of X & Y is (108000+72000)=180000
    Share Capital of Z is = 180000*5/10
    =90000

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