You have a network with a subnet of 172.16.17.0/22. Which is the valid host address?
A. 172.16.17.1 255.255.255.252
B. 172.16.0.1 255.255.240.0
C. 172.16.20.1 255.255.254.0
D. 172.16.18.255 255.255.252.0
Answer: Option D
Solution(By Examveda Team)
A Class B network ID with a /22 mask is 255.255.252.0, with a block size of 4 in the third octet. The network address in the question is in subnet 172.16.16.0 with a broadcast address of 172.16.19.255. Only option E even has the correct subnet mask listed, and 172.16.18.255 is a valid host.Related Questions on Subnetting
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B. 2 and 4
C. 1, 2 and 4
D. 2, 3 and 4
E. 2 and 5 only
A. 1 only
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D. 1 and 5 only
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