You have to find the sum of digits of a number given that the number is always greater than 0. Which of the following base cases can replace the base case for the below code?
#include<stdio.h>
int recursive_sum_of_digits(int n)
{
if(n == 0)
return 0;
return n % 10 + recursive_sum_of_digits(n/10);
}
int main()
{
int n = 1201;
int ans = recursive_sum_of_digits(n);
printf("%d",ans);
return 0;
}
#include<stdio.h>
int recursive_sum_of_digits(int n)
{
if(n == 0)
return 0;
return n % 10 + recursive_sum_of_digits(n/10);
}
int main()
{
int n = 1201;
int ans = recursive_sum_of_digits(n);
printf("%d",ans);
return 0;
}A. if(n == 0) return 1
B. if(n == 1) return 0
C. if(n == 1) return 1
D. no need to modify the base case
Answer: Option D
This Question Belongs to Data Structure >> Miscellaneous On Data Structures
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