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This question belongs to Arithmetic Ability Trigonometry
Trigonometry
?

$${\left( {\frac{{1 - \tan \theta }}{{1 - \cot \theta }}} \right)^2} + 1 = ?$$

Answer & Solution
Correct Answer: Option B
$$\eqalign{ & {\left( {\frac{{1 - \tan \theta }}{{1 - \cot \theta }}} \right)^2} + 1 \cr & = {\left( {\frac{{1 - \tan \theta }}{{\frac{{\tan \theta - 1}}{{\tan \theta }}}}} \right)^2} + 1 \cr & = \frac{{\left( {1 - \tan \theta } \right){{\tan }^2}\theta }}{{\left( {1 - \tan \theta } \right)}} + 1 \cr & = {\tan ^2}\theta + 1 \cr & = {\sec ^2}\theta \cr} $$
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