?
$${\left( {\frac{{1 - \tan \theta }}{{1 - \cot \theta }}} \right)^2} + 1 = ?$$
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& {\left( {\frac{{1 - \tan \theta }}{{1 - \cot \theta }}} \right)^2} + 1 \cr
& = {\left( {\frac{{1 - \tan \theta }}{{\frac{{\tan \theta - 1}}{{\tan \theta }}}}} \right)^2} + 1 \cr
& = \frac{{\left( {1 - \tan \theta } \right){{\tan }^2}\theta }}{{\left( {1 - \tan \theta } \right)}} + 1 \cr
& = {\tan ^2}\theta + 1 \cr
& = {\sec ^2}\theta \cr} $$
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