Maximum value of (2sinθ + 3cosθ) is?
A. 2
B. $$\sqrt {13} $$
C. $$\sqrt {15} $$
D. 1
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & \left( {2\sin \theta + 3\cos \theta } \right) \cr & {\text{Maximum value of}} \cr & a\sin \theta + b\cos \theta \cr & = \sqrt {{a^2} + {b^2}} \cr & = \sqrt {{2^2} + {3^2}} \cr & = \sqrt {4 + 9} \cr & = \sqrt {13} \cr} $$Related Questions on Trigonometry
A. x = -y
B. x > y
C. x = y
D. x < y
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