600 students took the test on Physics and chemistry. 35% students failed in Physics and 45% students failed in chemistry and 40% of those who passed in chemistry also passed in Physics, then how many students failed in both :
A. 16
B. 15
C. 13
D. 12
Answer: Option D
Solution(By Examveda Team)
| Result | Physics | Chemistry |
| Failed | 35% | 45% |
| Passed | 65% | 55% |
From question, 40% of those who passed in Chemistry(330 Students) also passed in physics
= $$\frac{{40 \times 330}}{{100}}$$
= 132,
so, 132 students passed in both
Therefore % who passed in both = $$\frac{{132 \times 100}}{{600}} = 22\% $$
Passed in both subject = 22% of total students % of students who passed in either Physics or Chemistry or both, = (65 + 55) - 22
= 98% Thus, percentage of students who failed in both subjects = 2% Number of students who failed = 2% of 600 = 12
This Question Belongs to Arithmetic Ability >> Percentage
Join The Discussion
Comments ( 5 )
Related Questions on Percentage
A. $$\frac{1}{4}$$
B. $$\frac{1}{3}$$
C. $$\frac{1}{2}$$
D. $$\frac{2}{3}$$
Physics failed = 35%,Pass = 65%
Chemistry failed = 45%, Pass = 55%, Both Pass = 40% of 55% = 22%
Total failed = 78%
so,
78% = 35%+ 45% - both
both = 2%
600 of 2%
= 12
How 22% came?
45% failed in chem => 55% passed in chem
35% failed in pay => 65% passed in pay
now, 55% of 600 passed in chem => 55/100*600 = 330
from question, 40% of those who passed in chem(i.e 330) also passed in pay => 40/100 *330 = 132 , so, 132 students passed in both
so % who passed in both = 132/600*100 = 22%
so, % of student who passed in any of the physics or chem or both (65% +55% -22%) =98%
so, the % of students who are failed in both =2% => 2/100*600 =>12
it is given that 40% of the students passed in both the subject how are u taking 22%
it is given that 40% of the students passed in both the subject how are u taking 22%