In an examination 80% candidates passed in English and 85% candidates passed in Mathematics. If 73% candidates passed in both these subjects, then what per cent of candidates failed in both the subjects?

Mohammed Aiaz 1 year ago

Just awesome.
Im grateful to find such kind of apps

Uttam Kokate 4 years ago

Total percentage =100
Pass E=80% m=85% both=73%
(E-both subject) 80-73=7
(M-both subject) 85-73= 12
73+12+7=92
92-100=8
=8%

Aarav Pardeep 4 years ago

Its so simple out of 100% 80% student passed in English and 85% passed in maths.73% passed in both.it mean out of 100% 73% passed in both,7% passed only in English(80-73) and 12% only in math(85-73).so after that left only 8 student who failed (100-73-7-12)

Bekelcha Muluneh 4 years ago

that's right

Israr Engineer 4 years ago

E union M,=(E+M)-(E intersection M)
let English represented by E
mathematics by M
put valu
=(80+85)-73
=92
number of students which is pass in both subject 92%
fail =total -pass
=100-92
=8%

Santanu Dash 5 years ago

8%

Appasani Manishankar 5 years ago

If price of petrol increases by 35% and Rajesh intends to spend only an additional 25% on petrol, by how much % will he reduce the quantity of petrol purchased?(Approx)

Lazy Dude 6 years ago

Use Set theory the problem will be easier

Upasyo Kushari, 6 years ago

Passed in english -80%
failed in english-(100-80)%
-20%
passed in maths -85%
failed in maths -(100-85)%
-15%
Total passed -100%-(20+15)%
-100%-35%
-65%
therefore,failed-73%-65%
-8%
ans.percentage-8

Hari Prasad 8 years ago

passed both only passed
maths 85 73 12
eng 80 73 7
total passed in both >>>12+7+73=92%
stu failed in both >>>> 100%-92%=8%

Priyanka Jayachandran 9 years ago

okay if they give no. students instead of each percentage,ans need to be in percentage means how to solve

Lalit Kumar 11 years ago

how is it posiable 92%student pass one sub. plese explan it