(719 + 2) is divided by 6. The remainder is :
A. 1
B. 2
C. 3
D. 5
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & \left( {{7^{19}} + 2} \right) \div 6 \cr & = \frac{{{{\left( {6 + 1} \right)}^{19}} + 2}}{6} \cr & = \frac{{{1^{19}} + 2}}{6} \cr & = 3\,{\text{remainder}} \cr} $$Alternate
(xn - an) is divisible by (x - a) for all values of n.
∴ (719 - 119) is divisible by (7 - 1)
⇒ (719 - 1) is divisible by 6
⇒ On dividing (719 + 2) by 6, remainder obtained = 3
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
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